variable assignment mathematica

The Wolfram Language's symbolic architecture supports a highly generalized notion of assignment, in which you can specify a transformation for any class of expressions defined by a Wolfram Language pattern. Simple cases correspond to assignments for "variables", "indexed variables", or "structure elements". Other cases define functions or general transformations.

$\begingroup$ I agree that often you just want to use rules, but in my case I'm trying to set a global variable before going on to solve for other things (where Solve will work better if it has this global value instead of trying to remain general for all possible values). I tried the equivalent of Set[sols[[1]]], and when that didn't work.Of course the "help" file is no help because it ...

If you expect to refer to a result later, you can assign it a name. For example, you can say thing= Range [10] to assign thing as a name for the result of Range [10]. You can assign a name to the result of a computation even if you never display the result. End your input with ; (semicolon) to avoid seeing the result.

The idea here is to assign automatically the variables a, b, c and x to a function so it becomes something like that: fn[x_,a_,b_,c_] := a*x^2 + b*x + c. In order to do this I've tried to extract the varibles from fn using Variables: Sort@Variables@fn. {a, b, c, x} Then in order to apply it to the function fn I do the following:

3. I have three questions about variable assignment. When I run the above code, it outputs 0. 1) If I run the same code outside the Module, it gives me 1. Why isn't the local z treated like the global case (which I can understand)? 2) If I remove the call to Evaluate (and run without the module), it again gives me 0.

Here's some unasked for help: PD.= does not have a syntactically-correct form, nor does P./; don't expect the variable pi to be interpreted to have the value 3.14159...; finally, it's unusual in Mathematica to make an assignment in a function to a variable with the same name as the function, a Module will return a value or values if you write it properly.

Mathematica is utilized a tool to analyze data. Here we demonstrate how to assign values to variables, comment code, and perform numerical operations.

Closed 3 years ago. Improve this question. For example in Python, if we have a list of 3 elements, say ls = [1,2,3] and we want to assign a variable to each value (from left to right), one can do as follows: x,y,z = ls where then, x will take the value 1 and so on. Now if we have a list in Mathematica ls = {1,2,3}, is there an analogous way of ...

1. Mathematica associates with each symbol a set of values. OwnValues is the one that stores value assignments to the symbol. This code returns the list of symbol names (as strings) for those symbols whose OwnValues is non-empty, i.e. the symbol has been assigned a value: Select[Names["Global`*"], ToExpression[#, InputForm, OwnValues ...

1. @tchronis You should not need the injector pattern here; a straightforward assignment will work: SetAttributes[assign, HoldFirst]; assign[association_, key_, val_] := association[key] = val. Much of the time I would just write out (asc[#] = #2) & however if I needed to apply that across a set of keys and values.

Abstract. We study single machine scheduling and common due-date assignment problems. The cost considered is fixed plus linear, i.e., jobs are penalized by two cost components: (i) a variable cost which is proportional to their earliness/tardiness values, (ii) a fixed cost which is independent of their actual earliness/tardiness values.

Here is an example code: a = 1; b = 1; c = a + b; f[x_, y_] := Module[{a = 3, b = 2, c}, c = (x + y)*(a + b)]; a,b,c are used outside of the function f and also inside f. How can I ensure that all used variables in a function are local WITHOUT specifing all of them in Module[{local variables},...]. This can be extremely annoying when I use many ...

removes all definitions but leaves the symbol intact: removes the symbol completely: has the attribute : This clears itself: This clears its value: Possible Issues (2) Protected symbols cannot be cleared: Use to clear definitions of protected symbols: When using a pattern without a context mark, all matching symbols on are cleared:

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