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Eureka Math Grade 5 Module 4 Lesson 8 Answer Key
Engage ny eureka math 5th grade module 4 lesson 8 answer key, eureka math grade 5 module 4 lesson 8 problem set answer key.
Question 1. Laura and Sean find the product of \(\frac{2}{3}\) × 4 using different methods. Laura: It’s 2 thirds of 4. \(\frac{2}{3}\) × 4 = \(\frac{4}{3}\) + \(\frac{4}{3}\) = 2 × \(\frac{4}{3}\) = \(\frac{8}{3}\)
Sean: It’s 4 groups of 2 thirds. \(\frac{2}{3}\) + \(\frac{2}{3}\) + \(\frac{2}{3}\) + \(\frac{2}{3}\) = 4 × \(\frac{2}{3}\) = \(\frac{8}{3}\) Use words, pictures, or numbers to compare their methods in the space below. Answer: Laura: 2/3 * 4 = 4/3 + 4/3 = 2*4/3 = 8/3 Sean: 2/3 + 2/3 + 2/3 + 2/3 = 4 * 2/3 = 8/3 Both methods are correct. 2/3 *4 is 2 thirds of 4, and it will also have the same product as the 4 groups of 2 thirds.
Question 2. Rewrite the following addition expressions as fractions as shown in the example. Example: \(\frac{2}{3}\) + \(\frac{2}{3}\) + \(\frac{2}{3}\) + \(\frac{2}{3}\) = (\(\frac{4 × 2}{3}\)) = \(\frac{8}{3}\) a. \(\frac{7}{4}\) + \(\frac{7}{4}\) + \(\frac{7}{4}\) = Answer: 21/4
Explanation: The addition expression for the fraction given is : 7/4 + 7/4 + 7/4 = (3 × 7)/4 = 21/4
b. \(\frac{14}{5}\) + \(\frac{14}{5}\) = Answer: 28/5
Explanation: The addition expression for the fraction given is : 14/5 + 14/5 = (2×14)/5 = 28/5
c. \(\frac{4}{7}\) + \(\frac{4}{7}\) + \(\frac{4}{7}\) = Answer: 12/7
Explanation: 4/7 +4/7 +4/7 = (3×4)/7 = 12/7
b. \(\frac{3}{5}\) × 10 10 × \(\frac{3}{5}\) Answer: 6
Explanation: 3 ×10/5 = 3 × 2 = 6 10 × 3/5 = (10×3)/5 = 30/5 = 6
a. 14 × \(\frac{3}{7}\) 14 × \(\frac{3}{7}\) Answer: 6
Explanation: (14×3)/7 = (7×2×3)/7 = (7×6)/7 = 6 (14 × 3)/7 = (2×3)/1 = 6
b. \(\frac{3}{4}\) × 36 \(\frac{3}{4}\) ×36 Answer: 27
Explanation: (3×36)/4 = (3×4×9)/4 = (4×27)/4 = 27 (3×36)/4 = (3×9) = (3×9) = 27
c. 30 × \(\frac{13}{10}\) 30 × \(\frac{13}{10}\) Answer: 39
Explanation: (30×13)/10 = (10×3×13)/10 = (10×39)/10 = 39 (30 ×13)/10 = (3×13)/1 = 39
d. \(\frac{9}{8}\) ×32 \(\frac{9}{8}\) × 32 Answer: 36
Explanation: (9×32)/8 = (9×4×8)/8 = (36×8)/8 = 36 (9×32)/8 = (9×32)/8 = (9×4)/1 = 36
Question 5. Solve each problem any way you choose. a. \(\frac{1}{2}\) × 60 \(\frac{1}{2}\) minute = __________ seconds Answer: 30seconds
Explanation: The answer and the procedure are explained clearly in the below steps. 1 minute = 60 seconds (1×60)/2 = (1×30)/1 = 30
b. \(\frac{3}{4}\) × 60 \(\frac{3}{4}\) hour = __________ minutes Answer: 45 minutes
Explanation: The answer and the procedure are explained clearly in the below steps. 1 hour = 60 minutes (3×60)/4 = (3×15)/1 = 45
c. \(\frac{3}{10}\) × 1,000 \(\frac{3}{10}\) kilogram = __________ grams” Answer: 300 grams
Explanation: The answer and the procedure are explained clearly in the below steps. 1 kilogram = 1000 grams (3×1000)/1 = 300
d. \(\frac{4}{5}\) × 100 \(\frac{4}{5}\) meter = __________ centimeters Answer: 80 centimeters
Explanation: The answer and the procedure are explained clearly in the below steps. 1 meter (4×100)/5 = (4×20)/1 = 80
Eureka Math Grade 5 Module 4 Lesson 8 Exit Ticket Answer Key
a. \(\frac{2}{3}\) × 15 \(\frac{2}{3}\) × 15 Answer: 10
Explanation: By solving the given question in two methods we could get the same answer i.e 10. The Explanation is given below. 2/3 × 15 = (2 ×15)/3 = 30/3 = 10 2/3 ×15 = (2×15)/3 = (2×5) = 10
b. \(\frac{5}{4}\) × 12 \(\frac{5}{4}\) × 12 Answer: 15
Explanation: By solving the given question in two methods we could get the same answer i.e 15. The process for the question is done below. 5/4 × 12 = (5×12)/4 = (60)/4 =15 5/4 ×12 = ( 5×12)/4 = (5×3) =15
Eureka Math Grade 5 Module 4 Lesson 8 Homework Answer Key
Question 1. Rewrite the following expressions as shown in the example. Example: \(\frac{2}{3}\) + \(\frac{2}{3}\) + \(\frac{2}{3}\) + \(\frac{2}{3}\) = (\(\frac{4 × 2}{3}\)) = \(\frac{8}{3}\)
a. \(\frac{5}{3}\) + \(\frac{5}{3}\) + \(\frac{5}{3}\) Answer: 5
Explanation: (\(\frac{3 × 5}{3}\)) = \(\frac{15}{3}\) =5
b. \(\frac{13}{5}\) + \(\frac{13}{5}\) Answer: \(\frac{26}{5}\)
Explanation: (\(\frac{2 × 13}{5}\)) = \(\frac{26}{5}\)
c. \(\frac{9}{4}\) + \(\frac{9}{4}\) + \(\frac{9}{4}\) Answer: \(\frac{27}{4}\)
Expalanation: (\(\frac{3 × 9}{4}\)) = \(\frac{27}{4}\)
a. \(\frac{3}{4}\) × 16 \(\frac{3}{4}\) × 16 Answer: 12
Explanation: (\(\frac{3 × 16}{4}\)) = \(\frac{48}{4}\) = 12 (\(\frac{3 × 16}{4}\)) = \(\frac{3 × 4}{1}\) = 12
b. \(\frac{4}{3}\) × 12 \(\frac{4}{3}\) × 12 Answer: 16
Explanation: (\(\frac{4 × 12}{3}\)) = \(\frac{48}{3}\) = 16 (\(\frac{4 × 12}{3}\)) = \(\frac{4 × 12}{1}\) = 16
c. 40 × \(\frac{11}{10}\) 40 × \(\frac{11}{10}\) Answer: 44
Explanation: (\(\frac{40 × 11}{10}\)) = \(\frac{440}{10}\) = 44 (\(\frac{40× 11}{10}\)) = \(\frac{4 × 11}{1}\) = \(\frac{44}{1}\) = 44
d. \(\frac{7}{6}\) × 36 \(\frac{7}{6}\)× 36 Answer: 42
Explanation: (\(\frac{7 × 36}{6}\)) = \(\frac{252}{6}\) = 42 (\(\frac{7 × 36}{6}\)) = \(\frac{7 × 6}{1}\) = 42
e. 24 × \(\frac{5}{8}\) 24 × \(\frac{5}{8}\) Answer: 15
Explanation: (\(\frac{24 × 5}{8}\)) = \(\frac{126}{8}\) = 15 (\(\frac{24 × 5}{8}\)) = \(\frac{3 × 5}{1}\) = 15
f. 18 × \(\frac{5}{12}\) 18 × \(\frac{5}{12}\) Answer: 7 1/2
Explanation: (\(\frac{18 × 5}{12}\)) = \(\frac{90}{12}\) = 7 6/12 = 7 1/2 (\(\frac{18 × 5}{12}\)) = \(\frac{3 × 5 }{2}\) = \(\frac{15}{2}\)= 7 1/2
g. \(\frac{10}{9}\) × 21 \(\frac{10}{9}\) × 21 Answer: 23 3/9 = 23 1/3
Explanation: (\(\frac{10 × 21}{9}\)) = \(\frac{210}{9}\) = 23 3/9 = 23 1/3 (\(\frac{10 × 21}{9}\)) = \(\frac{10 × 7}{3}\) = \(\frac{70}{3}\) = 23 1/3
Question 3. Solve each problem any way you choose.
a. \(\frac{1}{3}\) × 60 \(\frac{1}{3}\) minute = _________ seconds Answer: 20 seconds
Explanation: (\(\frac{1 × 60}{3}\)) = \(\frac{60}{3\) = 20
b. \(\frac{4}{5}\) × 60 \(\frac{4}{5}\) hour = _________ minutes Answer: 48 minutes
Explanation: (\(\frac{4 × 60}{5}\)) = \(\frac{48}{1\) = 48
c. \(\frac{7}{10}\) × 1000 \(\frac{7}{10}\) kilogram = _________ grams Answer: 700 grams
Explanation: (\(\frac{7 × 1000}{10}\)) = \(\frac{700}{1\) = 700
d. \(\frac{3}{5}\)× 100 \(\frac{3}{5}\) meter = _________ centimeters Answer: 60 centimeres
Explanation: (\(\frac{3 × 100}{5}\)) = \(\frac{60}{1\) = 60
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Eureka Math Grade 5 Module 4 Lesson 8 Problem Set Answer Key. Question 1. Laura and Sean find the product of 23 × 4 using different methods. Laura: It's 2 thirds of 4. 23 × 4 = 43 + 43 = 2 × 43 = 83. Sean: It's 4 groups of 2 thirds. 23 + 23 + 23 + 23 = 4 × 23 = 83. Use words, pictures, or numbers to compare their methods in the space below.
Relate a fraction of a set to the repeated addition interpretation of fraction multiplication, common core, fraction of a number, simplify fractions, help st...
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Engage NY // Eureka Math Grade 5 Module 4 Lesson 8 Homework. Engage NY // Eureka Math Grade 5 Module 4 Lesson 8 Homework.
Unit 5: Module 5: Addition and multiplication with volume and area. 0/1400 Mastery points. Topic A: Concepts of volume Topic B: Volume and the operations of multiplication and addition Topic C: Area of rectangular figures with fractional side lengths. Topic D: Drawing, analysis, and classification of two-dimensional shapes.
Eureka Essentials: Grade 4. An outline of learning goals, key ideas, pacing suggestions, and more! Fluency Games. Teach Eureka Lesson Breakdown. Downloadable Resources. Teacher editions, student materials, application problems, sprints, etc. Application Problems. Files for printing or for projecting on the screen.
@laurasetness6589 Connect repeated addition of fractions to multiplication, use cross-canceling as a strategy
5 GRADE Mathematics Curriculum GRADE 5 • MODULE 4 Module 4: Multiplication and Division of Fractions and Decimal Fractions Table of Contents GRADE 5 • MODULE 4 Multiplication and Division of Fractions and Decimal Fractions
As the creator of Engage NY Math and Eureka Math, Great Minds is the only place where you can get print editions of the PK-12 curriculum.Our printed materials are available in two configurations: Learn, Practice, Succeed, or student workbooks, teacher editions, assessment and fluency materials. The Learn, Practice, Succeed configuration is available for grades K-8 and offers teachers ...
Bundle options are available for all of our materials (print, digital, PD, etc.). Prices vary by grade and size of class set. Certain grade-levels do not include all packets due to the nature of the grade-level content. Student workbooks are available in class sets of 20, 25, and 30. Prices vary by size of class set.
Eureka Math. Eureka Math Grade 8 Module 4 Teacher Edition FL State Adoption Bid # 3693. ISBN 978-1-64054-364-5 Printed in the U.S.A. This book may be purchased from the publisher at eureka-math.org. 10 9 8 7 6 5 4 3 2 1 G8-M4-UTE-1.3.-05.2018 Published by ...
Unit 7: Module 7: Introduction to irrational numbers using geometry. Course challenge Test your knowledge of the skills in this course. Start Course challenge. Learn eighth grade math aligned to the Eureka Math/EngageNY curriculum —functions, linear equations, geometric transformations, and more.
Elektrostal , lit: Electric and Сталь , lit: Steel) is a city in Moscow Oblast, Russia, located 58 kilometers east of Moscow. Population: 155,196 ; 146,294 ...
Engage NY // Eureka Math Grade 5 Module 5 Lesson 4 Homework. Engage NY // Eureka Math Grade 5 Module 5 Lesson 4 Homework.
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It's Homework Time! Help for fourth graders with Eureka Math Module 5 Lesson 8.
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Elektrostal is a city in Moscow Oblast, Russia, located 58 kilometers east of Moscow. Elektrostal has about 158,000 residents. Mapcarta, the open map.
EngageNY/Eureka Math Grade 4 Module 5 Lesson 8For more videos, please visit http://bit.ly/eurekapusdPLEASE leave a message if a video has a technical difficu...